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JavaScript, based on Unique Random Numbers II, picks Unique Random Sets.
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JavaScript, based on Unique Random Numbers II, picks Unique Random Sets.
http://www.geocities.com/e_i_search/premshree/web-include/pub/scripts/JS/random_numbers2.htm
Here, there are more than one arrays (need not be of same length). First, we pick a number of unique random elements from the first array, numArr1 to form the array pickArr1. Now each element of pickArr1 picks another element from the second array numArr2, which again is unique and random. Thus we form the array pickArr2. Similarly each element of pickArr2 picks unique random elements from numArr3 to form pickArr3.
i.e if the first element of pickArr1 picks the second element of numArr2, then no other element of pickArr1 should pick the second element of numArr2 again JavaScript > Scripts and Programs > Randomizing > Combination Oct 12, 2006
i.e if the first element of pickArr1 picks the second element of numArr2, then no other element of pickArr1 should pick the second element of numArr2 again JavaScript > Scripts and Programs > Randomizing > Combination Oct 12, 2006
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Here, there are more than one arrays (need not be of same length). First, we pick a number of unique random elements from the first array, numArr1 to form the array pickArr1. Now each element of pickArr1 picks another element from the second array numArr2, which again is unique and random. Thus we form the array pickArr2. Similarly each element of pickArr2 picks unique random elements from numArr3 to form pickArr3.
i.e if the first element of pickArr1 picks the second element of numArr2, then no other element of pickArr1 should pick the second element of numArr2 again
i.e if the first element of pickArr1 picks the second element of numArr2, then no other element of pickArr1 should pick the second element of numArr2 again
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